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CBSE 2022 · Region 4 · Set 2 · Q10 · 3 marks

Write the Nernst equation and calculate the emf of the following cell at $\displaystyle 298$ K : $\displaystyle 3$ \[\mathrm{Zn}\left|\mathrm{Zn}^{2+}(0 \cdot 001 \mathrm{M}) \| \mathrm{H}^{+}(0 \cdot 01 \mathrm{M})\right| \mathrm{H}_{2}(\mathrm{~g})(1 \text { bar }) \mid \mathrm{Pt}(\mathrm{~s}) \] Given : $\displaystyle \mathrm{E}_{\mathrm{Zn}^{2+} / \mathrm{Zn}}=-0.76 \mathrm{~V}$ \[\mathrm{E}_{\mathrm{H}^{+} / \mathrm{H}_{2}}^{\ominus}=0.00 \mathrm{~V} \] $\displaystyle [\log 10=1]$

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