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CBSE 2022 · Region 4 · Set 3 · Q10 · 3 marks

Write the Nernst equation and calculate the emf of the following cell at $\displaystyle 298$ K : \[\mathrm{Zn}\left|\mathrm{Zn}^{2+}(0 \cdot 1 \mathrm{M}) \| \mathrm{Cd}^{2+}(0 \cdot 01)\right| \mathrm{Cd} \] Given : $\displaystyle \mathrm{E}_{\mathrm{Zn}^{2+} / \mathrm{Zn}}^{\ominus}=-0.76 \mathrm{~V}$ \[\mathrm{E}_{\mathrm{Cd}^{2+} / \mathrm{Cd}}^{\ominus}=-0 \cdot 40 \mathrm{~V} \] $\displaystyle (\log 10=1)$

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