Write the Nernst equation and calculate the emf of the following cell at 298 K: Zn | Zn^2+(0 · 1 M ) ∥ Cd^2+(0 · 01)| Cd Given: E_Zn^2+ / Zn^ =-0.76…

\[\begin{aligned} E_{\text {cell }} &=E_{\text {cell }}^{0}-\frac{0.059}{2} \log \frac{\left[\mathrm{Zn}^{2+}\right]}{\left[\mathrm{Cd}^{2+}\right]} \\ E_{\text {cell }}^{0} &=-0.40-(-0.76)=0.36 \mathrm{~V} \\ E_{\text {cell }} &=0.36-\frac{0.059}{2} \log \frac{\left[\mathrm{Zn}^{2+}\right]}{\left[\mathrm{Cd}^{2+}\right]} \\ &=0.36-\frac{0.059}{2} \log \frac{(0.1)}{(0.01)} \\ &=0.36-0.0295 \log 10 \\ E_{\text {cell }} &=0.3305 \mathrm{~V} \end{aligned} \]