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CBSE 2022 · Region 4 · Set 1 · Q10 · 3 marks

Write the Nernst equation and calculate emf of the following cell at $\displaystyle 298$ K : \[\mathrm{Cr}\left|\mathrm{Cr}^{3+}(0 \cdot 1 \mathrm{M}) \| \mathrm{Fe}^{2+}(0 \cdot 01 \mathrm{M})\right| \mathrm{Fe} \] Given : $\displaystyle \mathrm{E}_{\mathrm{Cr}^{3+} / \mathrm{Cr}}^{\ominus}=-0.75 \mathrm{~V}$ \[\mathrm{E}_{\mathrm{Fe}^{2+} / \mathrm{Fe}}^{\ominus}=-0.45 \mathrm{~V} \] $\displaystyle (\log 10=1)$

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