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Science · 2026 · 3 marks
CBSE 2026 · Region 2 · Set 1 · Q35
(a)Write the expression for the magnification produced by a lens in terms of object distance and image distance.(b)A $\displaystyle 4$ cm tall object is placed perpendicular to the principal axis of a convex lens of focal length $\displaystyle 20$ cm. Calculate the size of the image formed, if the distance of the object from the lens is $\displaystyle 10$ cm.
(a)
Write the expression for the magnification produced by a lens in terms of object distance and image distance.
(b)
A $\displaystyle 4$ cm tall object is placed perpendicular to the principal axis of a convex lens of focal length $\displaystyle 20$ cm. Calculate the size of the image formed, if the distance of the object from the lens is $\displaystyle 10$ cm.
Marking-scheme solution
(a) Magnification, \(\displaystyle \mathrm{m}=\frac{\text { Image distance }}{\text { Object distance }} / \mathrm{m}=\frac{\mathrm{v}}{\mathrm{u}}\)
(b) \[\begin{aligned}
& \mathrm{h}_{\mathrm{o}}=+4 \mathrm{~cm} \\
& \mathrm{f}=+20 \mathrm{~cm} \\
& \mathrm{u}=-10 \mathrm{~cm} \\
& \mathrm{~h}_{\mathrm{i}}=? \\
& \frac{1}{\mathrm{v}}-\frac{1}{\mathrm{u}}=\frac{1}{\mathrm{f}} \\
& \frac{1}{\mathrm{v}}=\frac{1}{\mathrm{f}}+\frac{1}{\mathrm{u}} \\
& \frac{1}{\mathrm{v}}=\frac{1}{20}+\frac{1}{-10} \\
& \frac{1}{\mathrm{v}}=\frac{-1}{20} \\
& \mathrm{v}=-20 \mathrm{~cm}
\end{aligned}
\]
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CBSE Class 10 Science past-paper question from the 2026board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.