Use the above given ray diagram to calculate the angle of incidence. Given that the refractive index of Medium 2 with respect to the Medium 1 is √ 3.

\[\begin{aligned} & \frac{\operatorname{Sin} i}{\operatorname{Sin} r}=n \\ & \angle r=90^{\circ}-60^{\circ}=30^{\circ} \end{aligned} \] Sin \(\displaystyle \mathrm{i}=\mathrm{n}\) Sin r \[\operatorname{Sin} \mathrm{i}=\sqrt{3} \operatorname{Sin} 30^{0} \] Sin \(\displaystyle \mathrm{i}=\sqrt{3} \times \frac{1}{2}\) \[\mathrm{i}=60^{\circ} \]