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Science · 2023 · 4 marks
CBSE 2023 · Region 4 · Set 1 · Q39
The ability of a medium to refract light is expressed in terms of its optical density. Optical density has a definite connotation. It is not the same as mass density. On comparing two media, the one with the large refractive index is optically denser medium than the other. The other medium with a lower refractive index is optically rarer. Also the speed of light through a given medium is inversely proportional to its optical density.(i)Determine the speed of light in diamond if the refractive index of diamond with respect to vacuum is 2.42. Speed of light in vacuum is $\displaystyle 3 \times 10^{8} \mathrm{~m} / \mathrm{s}$.(ii)Refractive indices of glass, water and carbon disulphide are $\displaystyle 1.5$, $\displaystyle 1.33$ and $\displaystyle 1.62$ respectively. If a ray of light is incident in these media at the same angle (say $\displaystyle \theta$ ) , then write the increasing order of the angle of refraction in these media.(iii)The speed of light in glass is $\displaystyle 2 \times 10^{8} \mathrm{~m} / \mathrm{s}$ and in water is $\displaystyle 2.25 \times 10^{8} \mathrm{~m} / \mathrm{s}$.(a)Which one of the two is optically denser and why?(b)A ray of light is incident normally at the water-glass interface when it enters a thick glass container filled with water. What will happen to the path of the ray after entering the glass? Give reason.The absolute refractive indices of water and glass are $\displaystyle 4$/$\displaystyle 3$ and $\displaystyle 3 / 2$ respectively. If the speed of light in glass is $\displaystyle 2 \times 10^{8} \mathrm{~m} / \mathrm{s}$, find the speed of light in (i) vacuum and (ii) water.
The ability of a medium to refract light is expressed in terms of its optical density. Optical density has a definite connotation. It is not the same as mass density. On comparing two media, the one with the large refractive index is optically denser medium than the other. The other medium with a lower refractive index is optically rarer. Also the speed of light through a given medium is inversely proportional to its optical density.
(i)
Determine the speed of light in diamond if the refractive index of diamond with respect to vacuum is 2.42. Speed of light in vacuum is $\displaystyle 3 \times 10^{8} \mathrm{~m} / \mathrm{s}$.
(ii)
Refractive indices of glass, water and carbon disulphide are $\displaystyle 1.5$, $\displaystyle 1.33$ and $\displaystyle 1.62$ respectively. If a ray of light is incident in these media at the same angle (say $\displaystyle \theta$ ) , then write the increasing order of the angle of refraction in these media.
(iii)
The speed of light in glass is $\displaystyle 2 \times 10^{8} \mathrm{~m} / \mathrm{s}$ and in water is $\displaystyle 2.25 \times 10^{8} \mathrm{~m} / \mathrm{s}$.
(a)
Which one of the two is optically denser and why?
(b)
A ray of light is incident normally at the water-glass interface when it enters a thick glass container filled with water. What will happen to the path of the ray after entering the glass? Give reason.
The absolute refractive indices of water and glass are $\displaystyle 4$/$\displaystyle 3$ and $\displaystyle 3 / 2$ respectively. If the speed of light in glass is $\displaystyle 2 \times 10^{8} \mathrm{~m} / \mathrm{s}$, find the speed of light in (i) vacuum and (ii) water.
Marking-scheme solution
(i) Refractive index of diamond \(\displaystyle =\frac{\text { Speed of light in vacuum }}{\text { Speed of light in diamond }}\) Speed of light in diamond \(\displaystyle =\frac{3 \times 10^{8} \mathrm{~m} / \mathrm{s}}{2.42}=1.23 \times 10^{8} \mathrm{~m} / \mathrm{s}\)
(ii) \(\displaystyle \angle \mathrm{r}\) in carbon disulphide \(\displaystyle <\angle \mathrm{r}\) in glass \(\displaystyle <\angle \mathrm{r}\) in water
(iii) (A)
(a) • Glass
The speed of light in water is more than the speed of light in glass. / Refractive index of glass is more than the refractive index of water.
(b) Light will enter from water to glass without bending (undeviated / straight) because in this case \(\displaystyle \angle \mathrm{i}=0 ; \angle \mathrm{r}=0\).
OR
(iii) (B)
\[\begin{aligned}
\mathrm{n}_{\text {glass }} & =\frac{3}{2} \\
\mathrm{n}_{\text {water }} & =\frac{4}{3} \\
\mathrm{~V}_{\text {glass }} & =2 \times 10^{8} \mathrm{~m} / \mathrm{s}
\end{aligned}
\]
\[\begin{aligned}
\mathrm{c}= & \mathrm{n}_{\text {glass }} \times \mathrm{v}_{\text {glass }} \\
& =\frac{3}{2} \times 2 \times 10^{8} \mathrm{~m} / \mathrm{s}
\end{aligned}
\]
\[=3 \times 10^{8} \mathrm{~m} / \mathrm{s}
\]
\[\mathrm{v}_{\text {water }}=\frac{c}{n_{\text {water }}}=\frac{3 \times 10^{8} \mathrm{~m} / \mathrm{s}}{\dfrac{4}{3}}
\]
\[=\frac{9}{4} \times 10^{8} \mathrm{~m} / \mathrm{s} \text { or } 2.25 \times 10^{8} \mathrm{~m} / \mathrm{s}
\]
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CBSE Class 10 Science past-paper question from the 2023board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.