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Science · 2024 · 2 marks
CBSE 2024 · Region 5 · Set 2 · Q25
Define power of a lens. Find power of a lens whose focal length is $\displaystyle 50$ cm.
Marking-scheme solution
Power of a lens is the reciprocal of focal length in metre./ It is the degree of convergence or divergence of light rays achieved by a lens.
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\[\mathrm{P}=\frac{1}{f}=\frac{100}{50}=2 \mathrm{D}
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CBSE Class 10 Science past-paper question from the 2024board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.