Physics · 2013
NEET 2013 · 18 May · Code Y · Q120
An electromagnetic wave of frequency ν=3.0 MHz passes from vacuum into a dielectric medium with relative permittivity ε=4.0. Then:
An electromagnetic wave of frequency $\displaystyle \nu=3.0 \mathrm{MHz}$ passes from vacuum into a dielectric medium with relative permittivity $\displaystyle \epsilon=4.0$. Then :
Official answer
(4)
Wavelength is halved and frequency remains unchanged.
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