Physics · 2012
NEET 2012 · Prelims · Code A · Q27
The electric field associated with an e.m. wave in vacuum is given by E = i 40 cos ( k z-6 × 10^8 t ), where E, z and t are in volt / m, meter and…
The electric field associated with an e.m. wave in vacuum is given by $\displaystyle \overrightarrow{\mathrm{E}}=\hat{i} 40 \cos \left(\mathrm{k} z-6 \times 10^8 \mathrm{t}\right)$, where $\displaystyle \mathrm{E}, z$ and $\displaystyle t$ are in volt $\displaystyle / \mathrm{m}$, meter and seconds respectively. The value of wave vector k is :
Official answer
(3)
$\displaystyle 2 \mathrm{~m}^{-1}$
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NEET (UG) 2012 Physics question, with the answer from NTA’s final answer key. Where our answers come from.