Physics · 2010
NEET 2010 · Mains · Code C · Q67
The electric field of an electromagnetic wave in free space is given by E =10 cos (10^7 t+k x) j V / m, where t and x are in seconds and metres…
The electric field of an electromagnetic wave in free space is given by
$\displaystyle \vec{E}=10 \cos \left(10^7 t+k x\right) \hat{j} \mathrm{~V} / \mathrm{m}$, where $\displaystyle t$ and $\displaystyle x$ are in seconds and metres respectively. It can be inferred that
(a)
The wavelength $\displaystyle \lambda$ is $\displaystyle 188.4$ m
(b)
The wave number $\displaystyle k$ is $\displaystyle 0.33 \mathrm{rad} / \mathrm{m}$
(c)
The wave amplitude is $\displaystyle 10$ V/m
(d)
The wave is propagating along $\displaystyle +x$ direction
Which one of the following pairs of statements is correct?
Official answer
(4)
(a) & (c)
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NEET (UG) 2010 Physics question, with the answer from NTA’s final answer key. Where our answers come from.