Physics · 2015
NEET 2015 · 3 May · Code E · Q35
A radiation of energy 'E' falls normally on a perfectly reflecting surface. The momentum transferred to the surface is ( C = Velocity of light):
A radiation of energy 'E' falls normally on a perfectly reflecting surface. The momentum transferred to the surface is ($\displaystyle \mathrm{C}=$ Velocity of light) :
Official answer
(2)
$\displaystyle \frac{2 \mathrm{E}}{\mathrm{C}}$
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