The standard cell potential of the following cell Zn | Zn^2+( aq )| Fe^2+( aq ) ∣ Fe is 0.32 V. Calculate the standard Gibbs energy change for the…

The standard cell potential of the following cell $\displaystyle \mathrm{Zn}\left|\mathrm{Zn}^{2+}(\mathrm{aq})\right| \mathrm{Fe}^{2+}(\mathrm{aq}) \mid \mathrm{Fe}$ is $\displaystyle 0.32$ V. Calculate the standard Gibbs energy change for the reaction : $$\mathrm{Zn}(\mathrm{~s})+\mathrm{Fe}^{2+}(\mathrm{aq}) \rightarrow \mathrm{Zn}^{2+}(\mathrm{aq})+\mathrm{Fe}(\mathrm{~s}) $$ (Given : $\displaystyle 1 \mathrm{~F}=96487 \mathrm{C}$ )