Calculate emf of the half cell given below: Pt(s) H 2( g, 2 atm) HCl(aq, 0.02 M) E H 2 / H^+^°=0 V (Given: (2.303 RT)/(F)=0.059, log 2=0.3010 )

Calculate emf of the half cell given below : $\displaystyle \mathrm{Pt}(\mathrm{s}) \mid \mathrm{H}_2(\mathrm{~g}, 2 \mathrm{~atm}) \mid \mathrm{HCl}(\mathrm{aq}, 0.02 \mathrm{M})$ $\displaystyle \mathrm{E}_{\mathrm{H}_2 / \mathrm{H}^{+}}^{\circ}=0 \mathrm{~V}$ (Given : $\displaystyle \frac{2.303 \mathrm{RT}}{\mathrm{F}}=0.059$, $\displaystyle \log 2=0.3010$ )