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Chemistry · 2026 · 4 marks

NEET 2026 · 21 June · Code 50 · Q56

The standard electrode potential ( E^° ) for the half-cell reaction Fe^3++e^- → Fe^2+ at 298 K is (Given: E^°(Fe^3+ / Fe)=-0.04 V and E^°(Fe^2+ /…

The standard electrode potential ( $\displaystyle \mathrm{E}^{\circ}$ ) for the half-cell reaction $\displaystyle \mathrm{Fe}^{3+}+\mathrm{e}^{-} \rightarrow$ $\displaystyle \mathrm{Fe}^{2+}$ at $\displaystyle 298$ K is (Given: $\displaystyle \mathrm{E}^{\circ}\left(\mathrm{Fe}^{3+} / \mathrm{Fe}\right)=-0.04 \mathrm{~V}$ and $\displaystyle \mathrm{E}^{\circ}\left(\mathrm{Fe}^{2+} / \mathrm{Fe}\right)=-0.44 \mathrm{~V}$ at $\displaystyle 298$ K )

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NEET (UG) 2026 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.