Given: (i) Cu^2++2 e^- → Cu, E^°=0.337 V (ii) Cu^2++ e^- → Cu^+, E^°=0.153 V Electrode potential, E^° for the reaction, Cu^++ e^- → Cu, will be:

Given: (i) Cu^2++2 e^- → Cu, E^°=0.337 V (ii) Cu^2++e^- → Cu^+, E^°=0.153 V Electrode…

Chemistry · 2009

Electrochemistry Nernst Equation

NEET 2009 · Prelims · Code A · Q57

Given :

(i)

$\displaystyle \mathrm{Cu}^{2+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Cu}, \mathrm{E}^{\circ}=0.337 \mathrm{~V}$

(ii)

$\displaystyle \mathrm{Cu}^{2+}+\mathrm{e}^{-} \rightarrow \mathrm{Cu}^{+}, \mathrm{E}^{\circ}=0.153 \mathrm{~V}$

Electrode potential, $\displaystyle \mathrm{E}^{\circ}$ for the reaction, $\displaystyle \mathrm{Cu}^{+}+\mathrm{e}^{-} \rightarrow \mathrm{Cu}$, will be :

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