In the electrochemical cell: Zn | ZnSO_4(0.01 M )|| CuSO_4(1.0 M )| Cu, the emf of this Daniel cell is E_1. When the concentration of ZnSO_4 is…

In the electrochemical cell : $\displaystyle \mathrm{Zn}\left|\mathrm{ZnSO}_4(0.01 \mathrm{M})\right|\left|\mathrm{CuSO}_4(1.0 \mathrm{M})\right| \mathrm{Cu}$, the emf of this Daniel cell is $\displaystyle \mathrm{E}_1$. When the concentration of $\displaystyle \mathrm{ZnSO}_4$ is changed to $\displaystyle 1.0$ M and that of $\displaystyle \mathrm{CuSO}_4$ changed to $\displaystyle 0.01$ M, the emf changes to $\displaystyle \mathrm{E}_2$. From the followings, which one is the relationship between $\displaystyle \mathrm{E}_1$ and $\displaystyle \mathrm{E}_2$ ? (Given, $\displaystyle \frac{\mathrm{RT}}{\mathrm{F}}=0.059$ )