Chemistry · 2019
NEET 2019 · 5 May · Code P1 · Q53
For the cell reaction 2 Fe^3+( aq )+2 I^-( aq ) → 2 Fe^2+( aq )+ I_2( aq ) E_cell^ =0.24 V at 298 K. The standard Gibbs energy (Δ_r G^ ) of the cell…
For the cell reaction
$\displaystyle 2 \mathrm{Fe}^{3+}(\mathrm{aq})+2 \mathrm{I}^{-}(\mathrm{aq}) \rightarrow 2 \mathrm{Fe}^{2+}(\mathrm{aq})+\mathrm{I}_2(\mathrm{aq})$
$\displaystyle \mathrm{E}_{\text {cell }}^{\ominus}=0.24 \mathrm{~V}$ at $\displaystyle 298$ K . The standard Gibbs energy $\displaystyle \left(\Delta_{\mathrm{r}} \mathrm{G}^{\ominus}\right)$ of the cell reaction is :
[Given that Faraday constant $\displaystyle \mathrm{F}=96500 \mathrm{C} \mathrm{mol}^{-1}$ ]
Official answer
From NTA’s final answer key for this paper.
(1)
$\displaystyle -46.32 \mathrm{~kJ} \mathrm{~mol}^{-1}$
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NEET (UG) 2019 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.