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NCERT Exemplar · Class 9 Science Improvement in Food Resources

49 questions · 49 still being checked

Long Answer Questions 46–49 (part 6 of 6)

  1. Exercise 46

    What would happen if poultry birds are larger in size and have no summer adaptation capacity? In order to get small sized poultry birds, having summer adaptability, what method will be employed?

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    NCERT’s answer
    Maintenance of temperature is needed for better egg production by poultry birds. Therefore, larger size (increase in surface area of body) and no adaptability of summer may cause decline in egg production. To obtain the smaller size and higher summer adaptability, cross breeding of poultry birds are done. Small size is also needed for better housing and low feed.
    In summer: \[\text{large body} + \text{no heat tolerance} \xrightarrow{\text{summer heat}} \text{heat stress} \] \[\text{heat stress} \Rightarrow \text{feed intake}\downarrow,\ \text{growth}\downarrow,\ \text{egg laying}\downarrow,\ \text{mortality}\uparrow \] To combine small body size and summer adaptability with high yield, a high-yielding exotic breed is cross-bred with an indigenous breed that tolerates heat and resists disease, and the progeny is selected for both traits together; small size also means less feed and housing space are needed. Answer: heat stress cuts egg laying and raises mortality; cross-breed a high-yielding exotic breed with a heat-tolerant, disease-resistant indigenous breed, selecting the progeny for both traits.
  2. Exercise 47

    Suggest some preventive measures for the diseases of poultry birds.

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    NCERT’s answer
    Some preventive measures of poultry bird diseases are (a) cleaning of poultry farms (b) proper sanitation of poultry farms (c) spraying of disinfectants at regular intervals (d) appropriate vaccination of birds.
    Clean, dry, well-ventilated housing with enough space per bird to prevent overcrowding.
    Disinfect the shed, feeders and waterers regularly.
    Clean water and balanced, uncontaminated feed.
    Vaccinate on schedule against common poultry diseases (e.g. Ranikhet, fowl pox).
    Quarantine and observe newly bought birds before mixing them with the flock.
    Remove sick birds promptly and dispose of dead birds by burning or deep burial.
    Control rodents and biting insects that carry infection between farms.
    Answer: hygienic, disinfected housing; clean feed and water; scheduled vaccination; quarantine of new birds; prompt removal and disposal of sick or dead birds; and rodent/insect control.
  3. Exercise 48

    Figure15.1 shows the two crop fields [Plots A and B] have been treated by
    manures and chemical fertilizers respectively, keeping other environmental
    factors same. Observe the graph and answer the following questions.
    (i)
    Why does plot B show sudden increase and then gradual decrease in yield?
    (ii)
    Why is the highest peak in plot A graph slightly delayed?
    (ii)
    What is the reason for the different pattern of the two graphs?
    NCERT_Question_Class9_Science_Exemplar_Ch15_Q48

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    NCERT’s answer
    (i)
    With addition of chemical fertilizer there is sudden increase in yield due to release of nutrients N,P,K etc in high quantity. The gradual decline in the graph may be due to continuous use and high quantity of chemicals which kills microbes useful for replenishing the organic matter in the soil. This decreases the soil fertility. (ii) Manures supply small quantities of nutrients to the soil slowly as it contains large amounts of organic matter [Hint: importance of organic matter can be included]. It enriches soil with nutrients thereby increasing soil fertility continuously. (iii) The difference in the two graphs indicate that use of manure is beneficial for long duration in cropping as the yield tends to remain high when the quantity of manure increases. In case of Plot B the chemical fertilizers may cause various problems when used continuously for long time. Loss of microbial activity reduces decomposition of organic matter and as a result soil fertility is lost that affects the yield.
    (i)
    Being readily soluble, chemical fertilizers are absorbed as soon as applied, so plot B's yield rises sharply. Beyond the optimum, continued use kills soil microorganisms and adds no organic matter, so yield declines as more is applied.
    (ii)
    Manures are organic matter: soil microbes must decompose them before nutrients release, so plot A's peak is delayed.
    (iii)
    Fertilizers give a fast boost but harm soil life; manures release nutrients slowly while improving soil texture and microbial activity, so the rise is slower and the decline gradual.
    Answer: (i) quick solubility, fast rise; then microbe damage drops yield (ii) microbial breakdown delays the peak (iii) manures build lasting soil health, fertilizers give only a fast, soil-harming pulse.
  4. Exercise 49

    Complete the crossword puzzle (Fig.15.2) Across 1. Oil yielding plant (9\displaystyle 9) 3. Crop grown in winter season (4\displaystyle 4) 5. Fixed by Rhizobium (8\displaystyle 8) 9. Common honey bee (4\displaystyle 4) Downward 2. Animal feed (6\displaystyle 6) 4. A micronutrient (5\displaystyle 5) 6. Unwanted plant in crop fields (4\displaystyle 4) 7. An exotic breed of chicken(7\displaystyle 7) 8. Bottom feeders in fish pond(7\displaystyle 7) 10. A marine fish (4\displaystyle 4) NCERT_Question_Class9_Science_Exemplar_Ch15_Q49

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    NCERT’s answer
    Crossword.
    Across — 1. Sunflower 3. Rabi 5. Nitrogen 9. Apis. Down — 2. Fodder 4. Boron 6. Weed 7. Leghorn 8. Mrigals 10. Tuna.Answer: Across: $\displaystyle 1$ Sunflower, $\displaystyle 3$ Rabi, $\displaystyle 5$ Nitrogen, $\displaystyle 9$ Apis. Down: $\displaystyle 2$ Fodder, $\displaystyle 4$ Boron, $\displaystyle 6$ Weed, $\displaystyle 7$ Leghorn, $\displaystyle 8$ Mrigals, $\displaystyle 10$ Tuna.