Physics · 2019
JEE Main · 8 April 2019, Shift 1 · Q16
Voltage rating of a parallel plate capacitor is 500 V. Its dielectric can withstand a maximum electric field of 10^6 V / m. The plate area is 10^-4…
Voltage rating of a parallel plate capacitor is $\displaystyle 500$ V . Its dielectric can withstand a maximum electric field of $\displaystyle 10^6 \mathrm{~V} / \mathrm{m}$. The plate area is $\displaystyle 10^{-4} \mathrm{~m}^2$. What is the dielectric constant if the capacitance is $\displaystyle 15$ pF ?
(given $\displaystyle \epsilon_0=8.86 \times 10^{-12} \mathrm{C}^2 / \mathrm{Nm}^2$ )
Official answer
(4)
$\displaystyle 8.5$
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JEE Main 2019 Physics question, with the answer from NTA’s final answer key. Where our answers come from.