Physics · 2021
JEE Main · 31 August 2021, Shift 2 · Q23
A parallel plate capacitor of capacitance 200 μ F is connected to a battery of 200 V. A dielectric slab of dielectric constant 2 is now inserted into…
A parallel plate capacitor of capacitance $\displaystyle 200 \mu \mathrm{~F}$ is connected to a battery of $\displaystyle 200$ V . A dielectric slab of dielectric constant $\displaystyle 2$ is now inserted into the space between plates of capacitor while the battery remain connected. The change in the electrostatic energy in the capacitor will be \_\_\_\_J.
Official answer
4
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