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Physics · 2026

JEE Main · 22 January 2026, Shift 2 · Q47

A capacitor P with capacitance 10 × 10^-6 F is fully charged with a potential difference of 6.0 V and disconnected from the battery. The charged…

A capacitor $\displaystyle P$ with capacitance $\displaystyle 10 \times 10^{-6} \mathrm{~F}$ is fully charged with a potential difference of $\displaystyle 6.0$ V and disconnected from the battery. The charged capacitor $\displaystyle P$ is connected across another capacitor $\displaystyle Q$ with capacitance $\displaystyle 20 \times 10^{-6} \mathrm{~F}$. The charge on capacitor $\displaystyle Q$ when equilibrium is established will be $\displaystyle \alpha \times 10^{-5}$ $\displaystyle C$ (assume capacitor $\displaystyle Q$ does not have any charge initially), the value of $\displaystyle \alpha$ is $\displaystyle \_\_\_\_$.
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JEE Main 2026 Physics question, with the answer from NTA’s final answer key. Where our answers come from.