Physics · 2021
JEE Main · 17 March 2021, Shift 1 · Q15
Two ideal polyatomic gases at temperatures T_1 and T_2 are mixed so that there is no loss of energy. If F_1 and F_2, m_1 and m_2, n_1 and n_2 be the…
Two ideal polyatomic gases at temperatures $\displaystyle \mathrm{T}_1$ and $\displaystyle \mathrm{T}_2$ are mixed so that there is no loss of energy. If $\displaystyle \mathrm{F}_1$ and $\displaystyle \mathrm{F}_2, \mathrm{~m}_1$ and $\displaystyle \mathrm{m}_2, \mathrm{n}_1$ and $\displaystyle \mathrm{n}_2$ be the degrees of freedom, masses, number of molecules of the first and second gas respectively, the temperature of mixture of these two gases is :
Official answer
(3)
$\displaystyle \frac{\mathrm{n}_1 \mathrm{~F}_1 \mathrm{~T}_1+\mathrm{n}_2 \mathrm{~F}_2 \mathrm{~T}_2}{\mathrm{n}_1 \mathrm{~F}_1+\mathrm{n}_2 \mathrm{~F}_2}$
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