Physics · 2026
JEE Main · 23 January 2026, Shift 2 · Q32
An air bubble of volume 2.9 cm^3 rises from the bottom of a swimming pool of 5 m deep. At the bottom of the pool water temperature is 17 °C. The…
An air bubble of volume $\displaystyle 2.9 \mathrm{~cm}^3$ rises from the bottom of a swimming pool of $\displaystyle 5$ m deep. At the bottom of the pool water temperature is $\displaystyle 17$ °C. The volume of the bubble when it reaches the surface, where the water temperature is $\displaystyle 27^{\circ} \mathrm{C}$, is $\displaystyle \_\_\_\_$ $\displaystyle \mathrm{cm}^3$.
( $\displaystyle \mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2$, density of water $\displaystyle =10^3 \mathrm{~kg} / \mathrm{m}^3$, and $\displaystyle 1$ atm pressure is $\displaystyle 10^5 \mathrm{~Pa}$ )
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle 4.5$
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JEE Main 2026 Physics question, with the answer from NTA’s final answer key. Where our answers come from.