Physics · 2021
JEE Main · 16 March 2021, Shift 2 · Q7
Calculate the value of mean free path ( λ ) for oxygen molecules at temperature 27^° C and pressure 1.01 × 10^5 Pa. Assume the molecular diameter 0.3…
Calculate the value of mean free path ( $\displaystyle \lambda$ ) for oxygen molecules at temperature $\displaystyle 27^{\circ} \mathrm{C}$ and pressure $\displaystyle 1.01 \times 10^5 \mathrm{~Pa}$. Assume the molecular diameter $\displaystyle 0.3$ nm and the gas is ideal. $\displaystyle \left(\mathrm{k}=1.38 \times 10^{-23} \mathrm{JK}^{-1}\right)$
Official answer
(4)
$\displaystyle 102$ nm
More from Kinetic Theory of Gases
- A flask contains argon and oxygen in the ratio of 3: 2 in mass and the mixture is kept at 27^° C. The ratio of their average kinetic energy per…2022
- A container of fixed volume contains a gas at 27°C. To double the pressure of the gas, the temperature of gas should be raised to ____ °C.2025
- On the basis of kinetic theory of gases, the gas exerts pressure because its molecules:2021
- The relation between root mean square speed ( v_rms ) and most probable speed ( v_p ) for the molar mass M of oxygen gas molecule at the temperature…2022
- A sample contains mixture of helium and oxygen gas. The ratio of root mean square speed of helium and oxygen in the sample, is:2024
- A gas mixture consists of 2 moles of oxygen and 4 moles of neon at temperature T. Neglecting all vibrational modes, the total internal energy of the…2023
- An air bubble of volume 2.9 cm^3 rises from the bottom of a swimming pool of 5 m deep. At the bottom of the pool water temperature is 17 °C. The…2026
- Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R Assertion A: If the average kinetic energy of…2026
JEE Main 2021 Physics question, with the answer from NTA’s final answer key. Where our answers come from.