Physics · 2016
JEE Main · 9 April 2016, Shift 1 · Q13
Three capacitors each of 4 μ F are to be connected in such a way that the effective capacitance is 6 μ F. This can be done by connecting them:
Three capacitors each of $\displaystyle 4 \mu \mathrm{~F}$ are to be connected in such a way that the effective capacitance is $\displaystyle 6 \mu \mathrm{~F}$. This can be done by connecting them :
Official answer
(2)
two in series and one in parallel
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JEE Main 2016 Physics question, with the answer from NTA’s final answer key. Where our answers come from.