Physics · 2019
JEE Main · 12 January 2019, Shift 1 · Q6
The position vector of the centre of mass r_cm of an asymmetric uniform bar of negligible area of cross-section as shown in figure is:
The position vector of the centre of mass $\displaystyle \vec{\mathrm{r}}_{\mathrm{cm}}$ of an asymmetric uniform bar of negligible area of cross-section as shown in figure is :
Official answer
(1)
$\displaystyle \overrightarrow{\mathrm{r}}_{\mathrm{cm}}=\frac{13}{8} \mathrm{~L} \hat{x}+\frac{5}{8} \mathrm{~L} \hat{y}$
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JEE Main 2019 Physics question, with the answer from NTA’s final answer key. Where our answers come from.