The minimum frequency of photon required to break a particle of mass 15.348 amu into 4 α particles is ____ kHz. [mass of He nucleus =4.002 amu, 1 amu…

The minimum frequency of photon required to break a particle of mass $\displaystyle 15.348$ amu into $\displaystyle 4 \alpha$ particles is $\displaystyle \_\_\_\_$ kHz. [mass of He nucleus $\displaystyle =4.002 \mathrm{amu}, 1 \mathrm{amu}=1.66 \times 10^{-27} \mathrm{~kg}, \mathrm{~h}=6.6 \times 10^{-34} \mathrm{~J}$.s and $\displaystyle \mathrm{c}=3 \times 10^8 \mathrm{~m} / \mathrm{s}$ ]