The energy released when 7/17.13 kg of _3^7 Li is converted into _2^4 He by proton bombardment is α × 10^32 eV. The value of α is ____. (Nearest…

The energy released when $\displaystyle \frac{7}{17.13} \mathrm{~kg}$ of $\displaystyle { }_3^7 \mathrm{Li}$ is converted into $\displaystyle { }_2^4 \mathrm{He}$ by proton bombardment is $\displaystyle \alpha \times 10^{32} \mathrm{eV}$. The value of $\displaystyle \alpha$ is $\displaystyle \_\_\_\_$. (Nearest integer) (Mass of $\displaystyle { }_3^7 \mathrm{Li}=7.0183 \mathrm{u}$, mass of $\displaystyle { }_2^4 \mathrm{He}=4.004 \mathrm{u}$, mass of proton $\displaystyle =1.008 \mathrm{u}$ and $\displaystyle 1 \mathrm{u}=931 \mathrm{MeV} / \mathrm{c}^2$ and Avogadro number $\displaystyle =6.0 \times 10^{23}$ )