Physics · 2024
JEE Main · 5 April 2024, Shift 1 · Q55
The electric field between the two parallel plates of a capacitor of 1.5 μ F capacitance drops to one third of its initial value in 6.6 μ s when the…
The electric field between the two parallel plates of a capacitor of $\displaystyle 1.5 \mu \mathrm{~F}$ capacitance drops to one third of its initial value in $\displaystyle 6.6 \mu \mathrm{~s}$ when the plates are connected by a thin wire.
The resistance of this wire is $\displaystyle \_\_\_\_$ $\displaystyle \Omega$. (Given, $\displaystyle \log 3=1.1$ )
Official answer
From NTA’s final answer key for this paper.
4
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JEE Main 2024 Physics question, with the answer from NTA’s final answer key. Where our answers come from.