Physics · 2025
JEE Main · 29 January 2025, Shift 2 · Q38
A capacitor, C_1=6 μ F is charged to a potential difference of V_0=5 V using a 5V battery. The battery is removed and another capacitor, C_2=12 μ F…
A capacitor, $\displaystyle \mathrm{C}_1=6 \mu \mathrm{~F}$ is charged to a potential difference of $\displaystyle \mathrm{V}_0=5 \mathrm{~V}$ using a 5V battery. The battery is removed and another capacitor, $\displaystyle \mathrm{C}_2=12 \mu \mathrm{~F}$ is inserted in place of the battery. When the switch ' S ' is closed, the charge flows between the capacitors for some time until equilibrium condition is reached. What are the charges ( $\displaystyle \mathrm{q}_1$ and $\displaystyle \mathrm{q}_2$ ) on the capacitors $\displaystyle \mathrm{C}_1$ and $\displaystyle \mathrm{C}_2$ when equilibrium condition is reached.

Official answer
From NTA’s final answer key for this paper.
(1)
$\displaystyle q_1=10 \mu C, q_2=20 \mu C$
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JEE Main 2025 Physics question, with the answer from NTA’s final answer key. Where our answers come from.