The disintegration energy Q for the nuclear fission of ^235 U →^140 Ce +^94 Zr +n is ____ MeV. Given atomic masses of ^235 U: 235.0439 u;^140 Ce:…

The disintegration energy $\displaystyle Q$ for the nuclear fission of $\displaystyle { }^{235} U \rightarrow{ }^{140} \mathrm{Ce}+{ }^{94} \mathrm{Zr}+n$ is $\displaystyle \_\_\_\_$ MeV.Given atomic masses of $\displaystyle { }^{235} \mathrm{U}: 235.0439 u ;{ }^{140} \mathrm{Ce}: 139.9054 u$, $$\begin{aligned} & { }^{94} \mathrm{Zr}: 93.9063 \mathrm{u} ; n: 1.0086 \mathrm{u}, \\ & \text { Value of } c^2=931 \mathrm{MeV} / \mathrm{u} . \end{aligned} $$