Physics · 2026
JEE Main · 23 January 2026, Shift 2 · Q37
The current passing through a conducting loop in the form of equilateral triangle of side 4 √ 3 cm is 2 A. The magnetic field at its centroid is α ×…
The current passing through a conducting loop in the form of equilateral triangle of side $\displaystyle 4 \sqrt{3} \mathrm{~cm}$ is $\displaystyle 2$ A. The magnetic field at its centroid is $\displaystyle \alpha \times 10^{-5} \mathrm{~T}$. The value of $\displaystyle \alpha$ is $\displaystyle \_\_\_\_$.
(Given : $\displaystyle \mu_{\mathrm{o}}=4 \pi \times 10^{-7}$ SI units)
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle 3 \sqrt{3}$
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JEE Main 2026 Physics question, with the answer from NTA’s final answer key. Where our answers come from.