Physics · 2026
JEE Main · 4 April 2026, Shift 2 · Q49
A circular coil of radius 2 cm and 125 turns carries a current of 1 A. The coil is placed in a uniform magnetic field of magnitude 0.4 T. The axis of…
A circular coil of radius $\displaystyle 2$ cm and $\displaystyle 125$ turns carries a current of $\displaystyle 1$ A . The coil is placed in a uniform magnetic field of magnitude $\displaystyle 0.4$ T. The axis of the coil makes an angle of $\displaystyle 30^{\circ}$ with the direction of the magnetic field. The torque acting on the coil is $\displaystyle \alpha \times 10^{-4} \mathrm{~N} . \mathrm{m}$. The value of $\displaystyle \alpha$ is $\displaystyle \_\_\_\_$.
( $\displaystyle \pi=3.14$ )
Official answer
From NTA’s final answer key for this paper.
314
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JEE Main 2026 Physics question, with the answer from NTA’s final answer key. Where our answers come from.