Physics · 2026
JEE Main · 4 April 2026, Shift 1 · Q41
An insulated wire is wound so that it forms a flat coil with N=200 turns. The radius of the innermost turn is r_1=3 cm, and of the outermost turn…
An insulated wire is wound so that it forms a flat coil with $\displaystyle N=200$ turns. The radius of the innermost turn is $\displaystyle r_1=3 \mathrm{~cm}$, and of the outermost turn $\displaystyle r_2=6 \mathrm{~cm}$. If $\displaystyle 20$ mA current flows in it then the magnetic moment will be $\displaystyle \alpha \times 10^{-2} \mathrm{~A} . \mathrm{m}^2$. The value of $\displaystyle \alpha$ is $\displaystyle \_\_\_\_$.
Official answer
From NTA’s final answer key for this paper.
(2)
$\displaystyle 2.64$
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JEE Main 2026 Physics question, with the answer from NTA’s final answer key. Where our answers come from.