Physics · 2026
JEE Main · 5 April 2026, Shift 2 · Q38
A particle of charge q and mass m is projected from origin with an initial velocity v =(v_0/(√ 2) x +v_0/(√ 2) y ). There exists a uniform magnetic…
A particle of charge $\displaystyle q$ and mass $\displaystyle m$ is projected from origin with an initial velocity $\displaystyle \vec{v}=\left(\frac{v_0}{\sqrt{2}} \hat{x}+\frac{v_0}{\sqrt{2}} \hat{y}\right)$. There exists a uniform magnetic field $\displaystyle \vec{B}=B_0 \hat{z}$ and a space varying electric field $\displaystyle \vec{E}=E_{\mathrm{o}} \mathrm{e}^{-\lambda x} \hat{x}$ within the region $\displaystyle 0 \leqslant x \leqslant L$. After travelling a distance such that $\displaystyle x$-coordinate has changed from $\displaystyle x=0$ to $\displaystyle x=L$, the change in the kinetic energy is $\displaystyle \_\_\_\_$.
Official answer
From NTA’s final answer key for this paper.
(1)
$\displaystyle \frac{q E_0}{\lambda}\left[1-e^{-\lambda L}\right]$
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JEE Main 2026 Physics question, with the answer from NTA’s final answer key. Where our answers come from.