The average energy released per fission for the nucleus of _92^235 U is 190 MeV. When all the atoms of 47 g pure _92^235 U undergo fission process,…

The average energy released per fission for the nucleus of $\displaystyle { }_{92}^{235} \mathrm{U}$ is $\displaystyle 190$ MeV . When all the atoms of $\displaystyle 47$ g pure $\displaystyle { }_{92}^{235} \mathrm{U}$ undergo fission process, the energy released is $\displaystyle \alpha \times 10^{23} \mathrm{MeV}$. The value of $\displaystyle \alpha$ is $\displaystyle \_\_\_\_$. $\displaystyle \left(\right.$ Avogadro Number $\displaystyle =6 \times 10^{23}$ per mole $\displaystyle )$