Physics · 2021
JEE Main · 27 August 2021, Shift 1 · Q28
The alternating current is given by i={√ 42 sin ((2 π)/T t )+10} A The r.m.s. value of this current is \ \ \ \ A.
The alternating current is given by
$$i=\left\{\sqrt{42} \sin \left(\frac{2 \pi}{\mathrm{~T}} \mathrm{t}\right)+10\right\} \mathrm{A}
$$
The r.m.s. value of this current is \_\_\_\_ A.
Official answer
11
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JEE Main 2021 Physics question, with the answer from NTA’s final answer key. Where our answers come from.