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Physics · 2021

JEE Main · 22 July 2021, Shift 2 · Q16

Match List - I with List - II: Choose the correct answer from the options given below:

Match List - I with List - II :
List - IList - II
(a)$\displaystyle \omega \mathrm{L}>\frac{1}{\omega \mathrm{C}}$(i)Current is in phase with emf
(b)$\displaystyle \omega \mathrm{L}=\frac{1}{\omega \mathrm{C}}$(ii)Current lags behind the applied emf
(c)$\displaystyle \omega \mathrm{L}<\frac{1}{\omega \mathrm{C}}$(iii)Maximum current occurs
(d)Resonant frequency(iv)Current leads the emf
Choose the correct answer from the options given below :
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JEE Main 2021 Physics question, with the answer from NTA’s final answer key. Where our answers come from.