Physics · 2023
JEE Main · 31 January 2023, Shift 2 · Q1
An alternating voltage source V =260 sin (628 t ) is connected across a pure inductor of 5 mH. Inductive reactance in the circuit is:
An alternating voltage source $\displaystyle \mathrm{V}=260 \sin (628 \mathrm{t})$ is connected across a pure inductor of $\displaystyle 5$ mH . Inductive reactance in the circuit is :
Official answer
From NTA’s final answer key for this paper.
(1)
$\displaystyle 3.14 \Omega$
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JEE Main 2023 Physics question, with the answer from NTA’s final answer key. Where our answers come from.