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Physics · 2024

JEE Main · 8 April 2024, Shift 2 · Q58

An alternating emf E =110 √ 2 sin 100 t volt is applied to a capacitor of 2 μ F, the rms value of current in the circuit is ____ mA.

An alternating emf $\displaystyle \mathrm{E}=110 \sqrt{2} \sin 100 \mathrm{t}$ volt is applied to a capacitor of $\displaystyle 2 \mu \mathrm{~F}$, the rms value of current in the circuit is $\displaystyle \_\_\_\_$ mA.
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JEE Main 2024 Physics question, with the answer from NTA’s final answer key. Where our answers come from.