Physics · 2020
JEE Main · 4 September 2020, Shift 1 · Q3
Starting from the origin at time t =0, with initial velocity 5 j ms^-1, a particle moves in the x-y plane with a constant acceleration of (10 i +4 j…
Starting from the origin at time $\displaystyle \mathrm{t}=0$, with initial velocity $\displaystyle 5 \hat{j} \mathrm{~ms}^{-1}$, a particle moves in the $\displaystyle x-y$ plane with a constant acceleration of $\displaystyle (10 \hat{i}+4 \hat{j}) \mathrm{ms}^{-2}$. At time t , its coordinates are $\displaystyle \left(20 \mathrm{~m}, y_0 \mathrm{~m}\right)$. The values of t and $\displaystyle y_0$ are, respectively :
Official answer
(3)
$\displaystyle 2$ s and $\displaystyle 18$ m
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JEE Main 2020 Physics question, with the answer from NTA’s final answer key. Where our answers come from.