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Physics · 2020
JEE Main · 9 January 2020, Shift 2 · Q2
A particle starts from the origin at t =0 with an initial velocity of 3.0 i m / s and moves in the x-y plane with a constant acceleration (6.0 i +4.0…
A particle starts from the origin at $\displaystyle \mathrm{t}=0$ with an initial velocity of $\displaystyle 3.0 \hat{i} \mathrm{~m} / \mathrm{s}$ and moves in the $\displaystyle x-y$ plane with a constant acceleration $\displaystyle (6.0 \hat{i}+4.0 \hat{j}) \mathrm{m} / \mathrm{s}^2$. The $\displaystyle x$-coordinate of the particle at the instant when its $\displaystyle y$ -coordinate is $\displaystyle 32$ m is D meters. The value of D is :
Official answer
(3)
$\displaystyle 60$
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JEE Main 2020 Physics question, with the answer from NTA’s final answer key. Where our answers come from.