The trajectory of a projectile in a vertical plane is y=α x-β x^2, where α and β are constants and x & y are respectively the horizontal and vertical…

The trajectory of a projectile in a vertical plane is $\displaystyle y=\alpha x-\beta x^2$, where $\displaystyle \alpha$ and $\displaystyle \beta$ are constants and $\displaystyle x$ & $\displaystyle y$ are respectively the horizontal and vertical distances of the projectile from the point of projection. The angle of projection $\displaystyle \theta$ and the maximum height attained H are respectively given by: