Physics · 2020
JEE Main · 3 September 2020, Shift 1 · Q4
Moment of inertia of a cylinder of mass M, length L and radius R about an axis passing through its centre and perpendicular to the axis of the…
Moment of inertia of a cylinder of mass M, length $\displaystyle L$ and radius $\displaystyle R$ about an axis passing through its centre and perpendicular to the axis of the cylinder is $\displaystyle \mathrm{I}=\mathrm{M}\left(\frac{\mathrm{R}^2}{4}+\frac{\mathrm{L}^2}{12}\right)$. If such a cylinder is to be made for a given mass of a material, the ratio L/R for it to have minimum possible I is :
Official answer
(1)
$\displaystyle \sqrt{\frac{3}{2}}$
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JEE Main 2020 Physics question, with the answer from NTA’s final answer key. Where our answers come from.