Physics · 2025
JEE Main · 2 April 2025, Shift 2 · Q28
The moment of inertia of a circular ring of mass M and diameter r about a tangential axis lying in the plane of the ring is:
The moment of inertia of a circular ring of mass M and diameter r about a tangential axis lying in the plane of the ring is :
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle \frac{3}{8} \mathrm{Mr}^2$
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JEE Main 2025 Physics question, with the answer from NTA’s final answer key. Where our answers come from.