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Physics · 2020

JEE Main · 3 September 2020, Shift 1 · Q3

A block of mass m=1 kg slides with velocity v=6 m / s on a frictionless horizontal surface and collides with a uniform vertical rod and sticks to it…

A block of mass $\displaystyle m=1 \mathrm{~kg}$ slides with velocity $\displaystyle v=6 \mathrm{~m} / \mathrm{s}$ on a frictionless horizontal surface and collides with a uniform vertical rod and sticks to it as shown. The rod is pivoted about O and swings as a result of the collision making angle $\displaystyle \theta$ before momentarily coming to rest. If the rod has mass $\displaystyle \mathrm{M}=2 \mathrm{~kg}$, and length $\displaystyle l=1 \mathrm{~m}$, the value of $\displaystyle \theta$ is approximately : (take $\displaystyle \mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2$ ) Figure: JEE Main Physics 2020, Rotational Motion
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JEE Main 2020 Physics question, with the answer from NTA’s final answer key. Where our answers come from.