Physics · 2018
JEE Main · 16 April 2018, Shift 1 · Q17
In the following circuit, the switch S is closed at t =0. The charge on the capacitor C_1 as a function of time will be given by (C_eq =(C_1…
In the following circuit, the switch S is closed at $\displaystyle \mathrm{t}=0$. The charge on the capacitor $\displaystyle \mathrm{C}_1$ as a function of time will be given by
$$\left(C_{\mathrm{eq}}=\frac{\mathrm{C}_1 \mathrm{C}_2}{\mathrm{C}_1+\mathrm{C}_2}\right)
$$
Official answer
(3)
$\displaystyle \mathrm{C}_{\mathrm{eq}} \mathrm{E}\left[1-\exp \left(-\mathrm{t} / \mathrm{RC}_{\mathrm{eq}}\right)\right]$
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JEE Main 2018 Physics question, with the answer from NTA’s final answer key. Where our answers come from.