Physics · 2019
JEE Main · 12 January 2019, Shift 1 · Q14
In the figure shown, after the switch ' S ' is turned from position 'A' to position 'B', the energy dissipated in the circuit in terms of capacitance…
In the figure shown, after the switch ' $\displaystyle S$ ' is turned from position 'A' to position 'B', the energy dissipated in the circuit in terms of capacitance ' $\displaystyle C$ ' and total charge ' $\displaystyle Q$ ' is :
Official answer
(4)
$\displaystyle \frac{3}{8} \frac{Q^2}{C}$
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JEE Main 2019 Physics question, with the answer from NTA’s final answer key. Where our answers come from.