Physics · 2016
JEE Main · 10 April 2016, Shift 1 · Q5
In the figure shown ABC is a uniform wire. If centre of mass of wire lies vertically below point A, then BC/AB is close to:
In the figure shown ABC is a uniform wire. If centre of mass of wire lies vertically below point A, then $\displaystyle \frac{\mathrm{BC}}{\mathrm{AB}}$ is close to :
Official answer
(2)
$\displaystyle 1.37$
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JEE Main 2016 Physics question, with the answer from NTA’s final answer key. Where our answers come from.