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Physics · 2024

JEE Main · 5 April 2024, Shift 1 · Q59

If three helium nuclei combine to form a carbon nucleus then the energy released in this reaction is ____ × 10^-2 MeV. (Given 1 u =931 MeV / c^2,…

If three helium nuclei combine to form a carbon nucleus then the energy released in this reaction is $\displaystyle \_\_\_\_$ $\displaystyle \times 10^{-2} \mathrm{MeV}$. (Given $\displaystyle 1 \mathrm{u}=931 \mathrm{MeV} / \mathrm{c}^2$, atomic mass of helium $\displaystyle =4.002603 \mathrm{u}$ )
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JEE Main 2024 Physics question, with the answer from NTA’s final answer key. Where our answers come from.